F(x)=16x^2+32x

Solution for F(x)=16x^2+32x equation:

(F)=16F^2+32F

We move all terms to the left:

(F)-(16F^2+32F)=0

We get rid of parentheses

-16F^2+F-32F=0

We add all the numbers together, and all the variables

-16F^2-31F=0

a = -16; b = -31; c = 0;
Δ = b2-4ac
Δ = -312-4·(-16)·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-31}{2*-16}=\frac{0}{-32}
=0
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+31}{2*-16}=\frac{62}{-32}
=-1+15/16
$